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Question
A glass flask is filled up to a mark with 50 cc of mercury at 18o C. If the flask and contents are heated to 38o C, how much mercury will be above the mark? ( for glass is 9×10−6/o C and coefficient of real expansion of mercury is 180×10−6/o C)
A glass flask is filled up to a mark with 50 cc of mercury at 18o C. If the flask and contents are heated to 38o C, how much mercury will be above the mark? ( for glass is 9×10−6/o C and coefficient of real expansion of mercury is 180×10−6/o C)
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Solution
The correct option is C 0.153 cc
Due to volume expansion of both mercury and flask, the change in volume of mercury relative to flask is given by
△V=V0[γl−γg]△θ=V[γm−3αg]△θ
=50[180×10−6−3×9×10−6](38−18)=0.153 cc
0.153 cc
Due to volume expansion of both mercury and flask, the change in volume of mercury relative to flask is given by
△V=V0[γl−γg]△θ=V[γm−3αg]△θ
=50[180×10−6−3×9×10−6](38−18)=0.153 cc
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