1
Question
A glass flask is filled up to a mark with 50 cc of mercury at 18∘C . If the flask and contents are heated to 38∘C , how much mercury will be above the mark ? (coefficient of linear expansion for glass is 9 × 10−6/∘C and coefficient of real expansion of mercury is 180 × 10−6/∘C)
A glass flask is filled up to a mark with 50 cc of mercury at 18∘C . If the flask and contents are heated to 38∘C , how much mercury will be above the mark ? (coefficient of linear expansion for glass is 9 × 10−6/∘C and coefficient of real expansion of mercury is 180 × 10−6/∘C)
Open in App
Solution
The correct option is C 0.153 cc
Due to volume expansion of both mercury and flask, the change in volume of mercury relative to flask is given by
△V=V0[γL−γg]△θ=V[γm−3αg]△θ
= 50 [ 180 ×10−6−3×9×10−6](38−18)=00.153cc
0.153 cc
Due to volume expansion of both mercury and flask, the change in volume of mercury relative to flask is given by
△V=V0[γL−γg]△θ=V[γm−3αg]△θ
= 50 [ 180 ×10−6−3×9×10−6](38−18)=00.153cc
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
