Question

A glass flask of volume one litre at $0^{\circ }C$ is filled full with mercury at this temperature. The flask and mercury are now heated to ${100}^{\circ }C$ .How much mercury will spill out, if coefficient of volume expansion of mercury is $1.82\times {10}^{-4}{/}^{\circ }C$ and linear expansion of glass is $0.1\times {10}^{-4}{/}^{\circ }C$ respectively?

• A. $1litre$
• B. $0.0172litre$
• C. $2.001litre$
• D. none of these

Answer 1

The correct option is B $0.0172litre$

The volume of glass$,$

$V=1+0.1\times {10}^{-4}\times 100=1.001litre$

the increase in volume of glass $\Delta V=1.001litre$

Now volume of mercury at ${100}^{0}C$ is given by$,$

$V_m=1+1.82\times {10}^{-4}\times 100=1.0182litre$

the amount of mercury will spill out $1.0182-1.0010=0.0172$ $litre$

Hence,

option $\left(B\right)$ is correct answer.