A glass marble whose mass is $200 g$ , falls from a height of $2.5 m$ and rebounds to a height of $1.6 m$ . Find the impulse acting due to its fall

4.9 N - s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8.8 N - s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.57 N - s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.52 N - s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $2.52 N - s$
Let $h_{2}$ be 2.5 $m$ and $h_{1}$ be 1.6 $m$ ,
We know Impulse is change in momemtum and velocity of glass marble at the time of hitting the ground and rebound can be calculted by relation $v = \sqrt{2 g h}$
Hence,
$I = Δ p = m (\to v - \to u)$
$= m [\sqrt (2 g h_{2}) - \sqrt (2 g h_{1})]$
$= 0.2 [7 - (- 5.6)] = 2.52 N - s$

Suggest Corrections

Similar questions

A glass marble whose mass is $200 g$ falls from a height of $2.5 m$ and rebounds to a height of $1.6 m$ . Find the change in momentum due to its rebound.

Q. A glass marble whose mass is

200 g

, falls from a height of

2.5 m

and rebounds to a height of

1.6 m

. Find the impulse acting due to its fall

Q. A glass marble whose mass is 20 gm, falls from a height of 2.5 m and rebounds to a height of 1.6 m. Find the change in momentum due to its fall

Q. A glass marble whose mass is

200 g m

, falls from a height of

2.5 m

and rebounds to a height of

1.6 m

. Find the change in momentum due to its fall.

Q. A glass marble, whose mass is

100 g m

, falls from a height of

20 m

and rebounds to a height of

5 m

. Find the impulse and average force between the marble and the floor, if the time during which they are in contact is

0.01 s e c

Join BYJU'S Learning Program

A glass marble whose mass is 200 g, falls from a height of 2.5 m and rebounds to a height of 1.6 m. Find the impulse acting due to its fall

A glass marble whose mass is $200 g$ , falls from a height of $2.5 m$ and rebounds to a height of $1.6 m$ . Find the impulse acting due to its fall