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Question

# A glass plate of thickness t is placed in front of one of the slits in a Young's double slit experiment. It is found that the interference pattern is shifted through a distance d. If this whole setup is immersed in water, the shift in pattern will be: [Given: Refractive index of glass, μg=32,Refractive index of water μw=43]

A
d4
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B
d2
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C
4d
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D
2d
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Solution

## The correct option is A d4The shift in interference pattern is given by, S=Dd(μ−1)t ∴S1S2=μ1−1μ2−1 Here, μ1=μg=32=1.5, and, μ2=μgμw=98=1.125 ∴S1S2=1.5−11.125−1 dS2=0.50.125 ∴S2=0.25 d=d4 Hence, (A) is the correct answer.

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