Question

A glass slab is placed in a medium of higher refractive index than glass. A light ray incident from one surface exits from opposite surface. Then,

• A. Angle of emergence = angle of incidence
• B. Emergent ray is parallel to incident ray
• C. Behaviour is similar to glass slab in air
• D. All of the above

Answer 1

The correct option is D All of the above

The effect of placing glass slab in a medium of higher index is that the emergent light ray will laterally shift in the opposite direction than that in air.

For first surface,

$\mu =sin\left(i\right)/sin\left(r\right)$............(1)

For second surface,

$1/\mu =sin\left(r\right)/sin\left(e\right)$.........(2)

From (1) and (2),

$sin\left(i\right)=sin\left(e\right)$

Hence, emergent ray is laterally shifted w.r.t incident ray. Thus, behavior is similar to glass slab in air.