Question

A glass slab $(\mu =1.5)$ of the thichness 2 cm is placed on a spot. The shift of spot if it is viewed from top is

• A. $\frac{1}{3}cm$
• B. $\frac{4}{3}cm$
• C. $\frac{5}{3}cm$
• D. $\frac{2}{3}cm$

Answer 1

The correct option is D $\frac{2}{3}cm$

$\text{Apparent depth =}\frac{\text{Real Depth}}{\mu }{t}^{\prime }=\frac{2}{\mu }=\frac{20}{15}=\frac{4}{3}{t}^{\prime }=\frac{4}{3}\Delta t=t-t^{\prime }=2-\frac{4}{3}=\frac{6-4}{3}=\frac{2}{3}cm$