Question

A glass slab of thickness $5cm$and refractive index $\raisebox{1ex}{$3$}\!\left/ \!\raisebox{-1ex}{$2$}\right.$ is placed over a photo. The apparent shift in position of the photo is ____ cm.

• A. $\raisebox{1ex}{$7$}\!\left/ \!\raisebox{-1ex}{$3$}\right.$
• B. $\raisebox{1ex}{$5$}\!\left/ \!\raisebox{-1ex}{$3$}\right.$
• C. $\raisebox{1ex}{$5$}\!\left/ \!\raisebox{-1ex}{$2$}\right.$
• D. $\raisebox{1ex}{$5$}\!\left/ \!\raisebox{-1ex}{$4$}\right.$

Answer 1

The correct option is B

$\raisebox{1ex}{$5$}\!\left/ \!\raisebox{-1ex}{$3$}\right.$

Step 1: Given data
The thickness of the glass slab $\left(t\right)=5cm$
Refractive index of glass slab $\left(n\right)=\frac{3}{2}$
Let the Apparent Shift be A.

Step 2: Calculating apparent shift
The apparent shift is given by:
$A=t\left(1-\frac{1}{n}\right)$
$\Rightarrow A=5\left(1-\frac{2}{3}\right)$
$\Rightarrow A=\frac{5}{3}$

Thus, the apparent shift of the photo is $\frac{5}{3}$.
Hence, option (B) is the correct answer.