A glass tube of volume 112 ml containing a gas is partially evacuated till the pressure in it drops to 3-8 - 10-5 torr at 00 C- The number of moleculesof the gas remaining in the tube isA- 4-5 - 1018B- 3 - 1017C- 1-5 - 1014D- 1-5 - 1019

The correct option is C 1.5 X 1014 PV=nRT n=PV/RT=3.8 × 10^ 5× 0.00131579 × 112 × 10^ 3/.082× 273 Since 1 atm is 0.00131579 torr =1.89 × 10^ 8 mol No. of molec ...

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Byju's Answer

Standard X

Chemistry

Mole Concept and Avogadro's Number

A glass tube ...

Question

A glass tube of volume 112 ml containing a gas is partially evacuated till the pressure in it drops to $3.8 \times 10^{- 5}$ torr at $0^{0} C$ . The number of molecules of the gas remaining in the tube is

3 X 10¹⁷

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1.5 X 10¹⁴

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4.5 X 10¹⁸

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1.5 X 10¹⁹

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Solution

The correct option is B
1.5 X 10¹⁴

PV=nRT
$n = \frac{P V}{R T} = \frac{3.8 \times 10^{- 5} \times 0.00131579 \times 112 \times 10^{- 3}}{.082 \times 273}$

Since 1 atm is 0.00131579 torr
$= 1.89 \times 10^{- 8} m o l$
No. of molecules = $0.02461 \times 10^{- 8} m o l$
$= 1.5 \times 10^{14}$

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A glass tube of volume 112 ml containing a gas is partially evacuated till the pressure in it drops to 3.8×10−5 torr at 00 C. The number of molecules of the gas remaining in the tube is

The correct option is B 1.5 X 1014 PV=nRT n=PVRT=3.8×10−5×0.00131579×112×10−3.082×273 Since 1 atm is 0.00131579 torr =1.89×10−8 mol No. of molecules = 0.02461×10−8 mol =1.5×1014

A glass tube of volume 112 ml containing a gas is partially evacuated till the pressure in it drops to $3.8 \times 10^{- 5}$ torr at $0^{0} C$ . The number of molecules of the gas remaining in the tube is

The correct option is B
1.5 X 10¹⁴

PV=nRT
$n = \frac{P V}{R T} = \frac{3.8 \times 10^{- 5} \times 0.00131579 \times 112 \times 10^{- 3}}{.082 \times 273}$

Since 1 atm is 0.00131579 torr
$= 1.89 \times 10^{- 8} m o l$
No. of molecules = $0.02461 \times 10^{- 8} m o l$
$= 1.5 \times 10^{14}$