A glass tube of volume 112 ml. containing gas is partially evacuated till the pressure in it drops to 3.8×10−1 torr at 25oC. The number of molecules of the gas remaining in the tube is:
A
3×1017
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B
1.5×1018
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C
4.5×1018
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D
6×1018
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Solution
The correct option is B1.5×1018 Volume= 112ml=0.112litre
Pressure= 3.8×10−1torr=0.0005atm
T=0oC=273K
PV=nRT
⇒n=0.0005×0.1120.0821×273=2.498×10−6 moles
The number of molecules of the gas remaining in the tube= 2.4018×10−6×6.023×1023=1.5×1018