A glass wind screen whose inclination with the vertical can be changed is mounted on a car- The car moves horizontally with a speed of 2 m - s- At what angle - with the vertical should the screen be placed so that the rain drops falling downwards with velocity 6 m - s strike the windscreen perpendicularly-A- tan -11-3B- tan -13C- cos -13D- sin -11-3

The correct option is A Velocity of rain with respect to car v_RC = v_R v_C should be perpendicular to the wind screen. i.e. net components of v_R tan α = ...

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Byju's Answer

Standard XII

Physics

Conductivity and Resistivity

A glass wind ...

Question

A glass wind screen whose inclination with the vertical can be changed is mounted on a car. The car moves horizontally with a speed of 2 m/s. At what angle $α$ with the vertical should the screen be placed so that the rain drops falling downwards with velocity 6 m/s strike the windscreen perpendicularly?

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Solution

The correct option is B. $t a n^{- 1} (3)$ .
Velocity of rain with respect to car $_{R C} =_{R} -_{C}$ should be perpendicular to the wind screen.
From the diagram above,
$t a n α = \frac{V_{R}}{V_{C}} = \frac{6}{2} = 3$
$α = t a n^{- 1} (3)$ .

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The correct option is B. tan−1(3).Velocity of rain with respect to car −−→vRC=−→vR−−→vC should be perpendicular to the wind screen. From the diagram above, tan α=VRVC=62=3α=tan−1(3).

The correct option is B. $t a n^{- 1} (3)$ .
Velocity of rain with respect to car $_{R C} =_{R} -_{C}$ should be perpendicular to the wind screen.
From the diagram above,
$t a n α = \frac{V_{R}}{V_{C}} = \frac{6}{2} = 3$
$α = t a n^{- 1} (3)$ .