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Question

A godown measures $$40\ m$$  $$\times 25\ m$$ $$\times 15\ m$$. Find the maximum of wooden crates each measuring $$1.5\ m$$ $$\times 1.25\ m$$ $$\times 0.5\ m$$ that can be stored in the godown.


Solution

$$\Rightarrow$$Volume of godown 
$$=l\times b\times h=40\times 25\times 15$$m$$^{3}$$
$$=15000$$m$$^{3}$$

$$\Rightarrow$$Volume of $$1$$ wooden crate
$$=1.5\times 1.25\times 0.5$$
$$=0.9375$$m$$^{3}$$

$$\Rightarrow$$No. of wooden crate stored in godown
$$=\cfrac{15000}{0.93750}$$
$$=16000$$

$$\therefore$$ $$16000$$ crates can be proved

Mathematics
RS Agarwal
Standard IX

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