A gold coin has a charge of $+ 10^{- 4} C$ . The number of electrons removed from it is:

10^{6}

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625 \times 10^{12}

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1.6 \times 10^{- 25}

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1.6 \times 10^{13}

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Solution

The correct option is B $625 \times 10^{12}$
The total charge of electrons removed from the coin would be equal to the positive charge acquired by the coin.
Thus, $10^{- 4} C = n \times 1.6 \times 10^{- 19} C$
$⟹ n = 625 \times 10^{12}$

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A gold coin has a charge of +10−4C. The number of electrons removed from it is:

The correct option is B 625×1012The total charge of electrons removed from the coin would be equal to the positive charge acquired by the coin.Thus, 10−4C=n×1.6×10−19C⟹n=625×1012

A gold coin has a charge of $+ 10^{- 4} C$ . The number of electrons removed from it is:

The correct option is B $625 \times 10^{12}$
The total charge of electrons removed from the coin would be equal to the positive charge acquired by the coin.
Thus, $10^{- 4} C = n \times 1.6 \times 10^{- 19} C$
$⟹ n = 625 \times 10^{12}$