Question

A goldsmith can choose between 3 metals A, B or C to make an artefact. He has 2 sheets of A, 3 sheets of B, 1 sheet of C and selected 1 sheet at random. What is the probability that he chooses C?

• A. 1/3
• B. 0
• C. 1
• D. 2/3

Answer 1

The correct option is C

1

The total number of sheets = 6

Number of sheets of C = 1

$P\left(C\right)=\frac{\text{Number of favourable outcomes}}{\text{Total number of possible outcomes}}$

where P(C) = Probability of getting metal C

=$\frac{\text{Number of sheets of C}}{\text{Total number of sheets}}$

= $\frac{1}{6}$.