A goldsmith can choose between 3 metals A, B or C to make an artefact. What is the probability that he chooses C?

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Solution

The correct option is A
1/3

Since the goldsmith can choose amongst A, B and C, he has 3 possibilities of which the favourable outcome is choosing C. Therefore, probability that he chooses C is $\frac{1}{3}$ .

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If $a \neq b \neq c$ such that
$∣ ∣ ∣ ∣ ∣ \begin{matrix} a^{3} - 1 & b^{3} - 1 & c^{3} - 1 a & b & c a^{2} & b^{2} & c^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣ = 0$ then,

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A goldsmith can choose between 3 metals A, B or C to make an artefact. What is the probability that he chooses C?

The correct option is A 1/3 Since the goldsmith can choose amongst A, B and C, he has 3 possibilities of which the favourable outcome is choosing C. Therefore, probability that he chooses C is 13.

The correct option is A
1/3

Since the goldsmith can choose amongst A, B and C, he has 3 possibilities of which the favourable outcome is choosing C. Therefore, probability that he chooses C is $\frac{1}{3}$ .