A government contractor who had a work-force of $560$ persons, undertook to complete a work in $8$ months. He was asked to complete the job in $7$ months. How many extra persons had he to pay ?

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Solution

$M_{1} D_{1} = M_{2} D_{2}$
$560 \times 8 = x \times 7$
$x = 640$
extra person $= 640 - 560 = 80$

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A government contractor who had a work-force of 560 persons, undertook to complete a work in 8 months. He was asked to complete the job in 7 months. How many extra persons had he to pay ?

M1D1=M2D2560×8=x×7x=640extra person =640−560=80

A government contractor who had a work-force of $560$ persons, undertook to complete a work in $8$ months. He was asked to complete the job in $7$ months. How many extra persons had he to pay ?

$M_{1} D_{1} = M_{2} D_{2}$
$560 \times 8 = x \times 7$
$x = 640$
extra person $= 640 - 560 = 80$