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Work Done in Isothermal Reversible Process

A gram mole o...

Question

A gram mole of a gas at $127^{o} C$ expands isothermally until its volume is doubled. find the amount of work done and heat absorbed.

238 c a l

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548 c a l

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548 J

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238 J

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Solution

The correct option is A $548 c a l$
Work done in an isothermal process is given as
$W = R T ln (\frac{V_{2}}{V_{1}})$
$= 8.314 \times 400 \times ln 2$
$= 2310.1 J = 548 c a l$

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