wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A graph between current and time during charging of a capacitor by a battery in series with a resistor is shown. The graphs are drawn for two circuits. Here R1,R2,C1,C2 and V1,V2 are the values of resistances, capacitances and EMF of cells in the two circuits. If only two parameters out of resistance, capacitance, emf are different in two circuits. What will be the correct option?


A
V1=V2, R1>R2, C1>C2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
V1>V2, R1>R2, C1=C2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
V1<V2, R1<R2, C1=C2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
V1<V2, R1=R2, C1<C2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C V1<V2, R1<R2, C1=C2

The current at any time t is given by,I=I0et/RCAs, I0=VR

I=VRet/RC

Taking ln on both sides we have,

lnI=ln(VR)+tRClne

lnI=ln(VR)tRC .....(1)

For the plotting of lnI vs t, it can be inferred from equation (1) that it will be a straight line with, slope |m|=1RC and Intercept=ln(VR)

From the given graph,

(Intercept)1=(Intercept)2

and |(slope)1|>|(slope)2|

It is only possible if R1<R2 and V1<V2 such that ln(VR) remains unaffected & |m2|<|m1| is achieved.

V1<V2, R1<R2, C1=C2
(c) is the correct answer.

flag
Suggest Corrections
thumbs-up
4
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon