Question

a graph is plotted b/w log₁₀K and 1/T for Arrhenius equation. Then the value of slope is found -1/R.Then find out the value of E_a.

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{When}\mathrm{a}\mathrm{graph}\mathrm{is}\mathrm{plotted}\mathrm{between}{\log }_{10}\mathrm{k}\mathrm{and}\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$\mathrm{T}$}\right.,\mathrm{a}\mathrm{straight}\mathrm{line}\mathrm{with}\mathrm{a}\mathrm{negative}\mathrm{slope}\mathrm{is}\mathrm{obtained}. \\ \mathrm{Slope}=\frac{-{\mathrm{E}}_{\mathrm{a}}}{2.303\mathrm{R}} \\ \mathrm{or},{\mathrm{E}}_{\mathrm{a}}=-2.303\mathrm{R}.\mathrm{slope} \\ \mathrm{Here},\mathrm{slope}=\frac{-1}{\mathrm{R}} \\ \mathrm{Therefore},{\mathrm{E}}_{\mathrm{a}}=-2.303\mathrm{R}\times \left(\frac{-1}{\mathrm{R}}\right) \\ \mathrm{or}{\mathrm{E}}_{\mathrm{a}}=2.303 \end{gathered}$$