A graph is plotted between P(atm) vs $t^{o} C$ for 10 mol of an ideal gas as follows :
Then slope of curve and volume of container (L) respectively, are :

0.1, 8.21

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8.21, 0.1

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27.3, 8.21

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8.21, 27.3

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Solution

The correct option is A 0.1, 8.21
$y -$ axis $= P x -$ axis $= T (^{o} C)$
$P = m T + C$
$T = 0 \Rightarrow P = 27.3$ $a t m \Rightarrow C = 27.3$
$p = m T + 27.3$ equation $1$
Ideal gas equation:
$P V = n R T (T$ in $K)$
Volume at $0^{o} C (273$ $K)$
$27.3 \times V = 10 \times 0.0821 \times 273$
$V = 8.21$ $L i t r e s$
Ideal gas equation in $^{o} C$
$P V = n R (T + 273)$
$n = 10, R = 0.0821, V = 8.21$
$P = \frac{n R}{T} + \frac{n R}{V} \times 273$
$P = 0.1 T + 27.3$ equation $2$
Comparing $2$ with $1$
slope $= M = 0.1$

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A graph is plotted between P(atm) vs toC for 10 mol of an ideal gas as follows :Then slope of curve and volume of container (L) respectively, are :

A graph is plotted between P(atm) vs $t^{o} C$ for 10 mol of an ideal gas as follows :
Then slope of curve and volume of container (L) respectively, are :