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Question

A graph is plotted between P(atm) vs toC for 10 mol of an ideal gas as follows :
Then slope of curve and volume of container (L) respectively, are :
1058148_17e8ee5145684d4880365d8a866bfada.png

A
0.1, 8.21
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B
8.21, 0.1
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C
27.3, 8.21
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D
8.21, 27.3
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Solution

The correct option is A 0.1, 8.21
yaxis =Pxaxis =T(oC)
P=mT+C
T=0P=27.3 atmC=27.3
p=mT+27.3 equation 1
Ideal gas equation:
PV=nRT(T in K)
Volume at 0oC(273 K)
27.3×V=10×0.0821×273
V=8.21 Litres
Ideal gas equation in oC
PV=nR(T+273)
n=10,R=0.0821,V=8.21
P=nRT+nRV×273
P=0.1T+27.3 equation 2
Comparing 2 with 1
slope =M=0.1

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