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A graph is pl...

Question

A graph is plotted between velocity ( $v$ ) and displacement ( $s$ ) of particle moving in a straight line. Here $v$ is plotted along y-axis and $s$ along x-axis. Choose the correct option

slope of this graph at any point always gives us the ratio of displacement and velocity at that point

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slope represents

\frac{a}{v}

(

a

= acceleration)

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both A and B are correct

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both A and B are wrong

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Solution

The correct option is B slope represents $\frac{a}{v}$ ( $a$ = acceleration)
$\frac{d v}{d s} = \frac{d v}{d t} . \frac{d t}{d s}$
So slope of velocity vs displacement graph is $\frac{a}{v}$ .
Because $\frac{d v}{d t} = a, \frac{d s}{d t} = v$
Hence only option B is correct.

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A graph is plotted between velocity (v) and displacement (s) of particle moving in a straight line. Here v is plotted along y-axis and s along x-axis. Choose the correct option

The correct option is B slope represents av (a = acceleration)dvds=dvdt.dtdsSo slope of velocity vs displacement graph is av.Because dvdt=a,dsdt=vHence only option B is correct.

A graph is plotted between velocity ( $v$ ) and displacement ( $s$ ) of particle moving in a straight line. Here $v$ is plotted along y-axis and $s$ along x-axis. Choose the correct option

The correct option is B slope represents $\frac{a}{v}$ ( $a$ = acceleration)
$\frac{d v}{d s} = \frac{d v}{d t} . \frac{d t}{d s}$
So slope of velocity vs displacement graph is $\frac{a}{v}$ .
Because $\frac{d v}{d t} = a, \frac{d s}{d t} = v$
Hence only option B is correct.