Question

A graph of $\ln k$ vs $\left(\frac{1}{T}\right)$ has slope equal to

• A. $-\frac{E}{2.303R}$
• B. $+\frac{E_a}{R}$
• C. $-\frac{E_a}{2.303R}$
• D. $-\frac{E_a}{R}$

Answer 1

The correct option is D $-\frac{E_a}{R}$

We know that $lnk=\frac{-E_a}{RT}+lnA$

Option D is correct.