A graph of stopping potential Vs versus frequency - of incident light is shown below- Find the work function of the metal- -Use 1 eV - 1-6 - 10-19 C- - Vs - - - - - - - - - - - - - - - - - - - - 1 eV - 1-6 - 10-19 C-

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Saturation Current

A graph of st...

Question

A graph of stopping potential (V_s) versus frequency (ν) of incident light is shown below. Find the work function of the metal. [Use 1 eV = 1.6 × 10^–19C]

निरोधी विभव (V_s) तथा आपतित प्रकाश की आवृत्ति (ν) के मध्य ग्राफ नीचे दिया गया है। धातु का कार्यफलन ज्ञात कीजिए। [प्रयोग करेंः 1 eV = 1.6 × 10^–19C]

250 eV

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4 eV

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2.5 eV

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400 eV

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| V_{s} |

V_{s}

V_{0}

v

e V

V_{0} (in V)

ν (in Hz)

(in eV)

V_{0} (i n V)

ν (i n Hz)

h = 6.6 \times 10^{- 34} J s

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