A graph of volume of hydrogen released vs time for the reaction between zinc and dil. $H C l$ is given. Find the instantaneous rate of reaction at 40 sec is :

\frac{V_{3} - V_{2}}{40}

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\frac{V_{2} - V_{1}}{20}

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\frac{V_{3} - V_{1}}{40}

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Solution

The correct option is C $\frac{V_{3} - V_{1}}{40}$
Instantaneous rate of reaction is given by the slope of the curve at the point.
slope is given by :
$A v e r a g e = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{V_{3} - V_{1}}{t_{3} - t_{1}} = \frac{V_{3} - V_{1}}{40}$

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Similar questions

A graph of volume of hydrogen released vs time for the reaction between zinc and dil. HCl is given in the figure. On the basis of this mark the correct option.

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(c) Average rate upto 40 s is $\frac{V_{3}}{40}$
(d) Average rate upto 40 s is $\frac{V_{3} - V_{1}}{40 - 20}$

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A graph of volume of hydrogen released vs time for the reaction between zinc and dil. HCl is given. Find the instantaneous rate of reaction at 40 sec is :

The correct option is C V3−V140Instantaneous rate of reaction is given by the slope of the curve at the point.slope is given by :Average=y2−y1x2−x1=V3−V1t3−t1=V3−V140

A graph of volume of hydrogen released vs time for the reaction between zinc and dil. $H C l$ is given. Find the instantaneous rate of reaction at 40 sec is :

The correct option is C $\frac{V_{3} - V_{1}}{40}$
Instantaneous rate of reaction is given by the slope of the curve at the point.
slope is given by :
$A v e r a g e = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{V_{3} - V_{1}}{t_{3} - t_{1}} = \frac{V_{3} - V_{1}}{40}$