Question

A green solution of potassium manganate (VI) turns purple and a brown solid is precipitated, when $C{O}_2$ gas is bubbled through the solution.

The purple colour is due to the formation of X, and the brown solid that is precipitated is Y. X and Y respectively are:

• A. Manganese dioxide (IV), Potassium permanganate (VIII)
• B. Potassium permanganate (VII), Manganese dioxide (IV)
• C. Potassium permanganate (VIII), Manganese oxide (II)
• D. Manganese oxide (II), Manganese trioxide (III)

Answer 1

The correct option is B Potassium permanganate (VII), Manganese dioxide (IV)

$3K_{2}Mn{O}_4+2C{O}_2\to \underset{purple}{2KMn{O}_4}+\underset{\left(brownsolid\right)}{Mn{O}_2}+2K_{2}C{O}_3$