A green solution of potassium manganate (VI) turns purple and a brown solid is precipitated, when $C O_{2}$ gas is bubbled through the solution.

The given experiment involves:

An acid – base reaction

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A redox reaction

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A disproportionation reaction

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A decomposition reaction

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Solution

The correct option is C A disproportionation reaction
$K_{2} M n O_{4} + 2 H_{2} O + 4 C O_{2} \to 2 K M n O_{4} (p u r p l e) + M n O_{2} (b r o w n s o l i d) + 2 K H C O_{3}$

In the above reaction the oxidation state of $M n$ changes from +6 ( $K_{2} M n O_{4}$ ) to +4 ( $M n O_{2}$ ) and +7 ( $K M n O_{4}$ ) so the same species is getting oxidised and reduce, hence it is a disproportionation reaction

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C O_{2} + H_{2} O ⇌ H_{2} C O_{3} ⇌ H^{+} + H C O_{3}^{-}

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