Question

A grocery bag can carry a maximum weight of 2 kg. Calculate the minimum number of bags required to carry the weight of all the following items:

$\text{Flour:}1\frac{4}{5}\text{kg}$

$\text{Sugar:}\frac{9}{10}\text{kg}$

• A. 1 bag
• B. 2 bags
• C. 3 bags
• D. 4 bags

Answer 1

The correct option is B 2 bags

Let us find the weight of all the items to be carried by the grocery bag.

$\text{Flour:}1\frac{4}{5}\text{kg}$

$\text{Sugar:}\frac{9}{10}\text{kg}$

$\therefore \text{Total weight of all the items to be carried}$
$=[1\frac{4}{5}+\frac{9}{10}]\text{kg}$

$\text{Now,}1\frac{4}{5}\text{can be expressed as:}$


$\text{Similarly,}\frac{9}{10}\text{can be represented as:}$


$\text{So,}1\frac{4}{5}+\frac{9}{10}=\frac{18}{10}+\frac{9}{10}$

$\text{Calculating}\frac{18}{10}+\frac{9}{10}\text{, we get:}$


$\text{Rewriting}\frac{27}{10}\text{, we get:}$


$\text{So, the combined weight of the flour and sugar}$
$\text{to be carried is}2\frac{7}{10}\text{kg.}$

But, a single bag can only carry a maximum of 2 kg of groceries.

∴ At the minimum, 2 grocery bags are required to carry the given amount of groceries.