Question

A group consists of 12 persons, of which 3 are extremely patient, other 6 are extremely honest and rest are extremely kind. A person from the group is selected at random. Assuming that each person is equally likely to be selected, find the probability of selecting a person who is

(i) extremely patient

(ii) extremely kind or honest.

Which of the above values you prefer more? [4 MARKS]

Answer 1

Solution: 4 Marks

Total number of persons in the group = 12

(i) Number of persons who are extremely patient = 3

P(selecting a person who is extremely patient) $=\frac{3}{12}=\frac{1}{4}$

(ii) Number of persons who are extremely honest = 6

Number of persons who are extremely kind = 12 - (3 + 6) = 3

$\therefore$ P(selecting a person who is extremely kind or extremely honest) = $\frac{3+6}{12}=\frac{9}{12}=\frac{3}{4}$

From the given three values, we prefer honesty. Honesty can get rid of rampant corruption which is a burning issue of the present society.