A group consists of equals number of men and women. Of this group, 20% of the men and 50% of the women are unemployed. If a person is selected at random from this group, the probability of the selected person being employed is
0.65
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Solution
The correct option is A 0.65 Let
A = {Employed Person}; E1={Selected Person in Men} E2={Selected Person in Women}
By total probability, P(A)=P(E1).P(A/E1)+P(E2).P(A/E2) =0.5×0.8+0.5×0.5 =0.4+0.25 =0.65