A group of 100 people plays carrom, snooker and chess. 90 people play chess, 80 people play snooker and 80 people play carom. Find the maximum number of people who play all 3 games, if each person plays at least one game.

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Solution

The correct option is C
75

S= 90+80+80=250

X= 100

Using the Maxima of all shortcut
$\frac{S - X}{N - 1} = \frac{150}{2} = 75$

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A group of 100 people plays carrom, snooker and chess. 90 people play chess, 80 people play snooker and 80 people play carom. Find the maximum number of people who play all 3 games, if each person plays at least one game.

The correct option is C 75S= 90+80+80=250 X= 100 Using the Maxima of all shortcut S−XN−1=1502=75

The correct option is C
75

S= 90+80+80=250

X= 100

Using the Maxima of all shortcut
$\frac{S - X}{N - 1} = \frac{150}{2} = 75$