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Series Combination of Cells

A group of ...

Question

A group of $N$ cells whose emf varies directly with the internal resistance as per the equation $E_{N} = 1.5 r_{N}$ are connected as shown in the figure above. The current $I$ in the circuit is:

5.1 A

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0.51 A

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1.5 A

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0.15 A

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Solution

The correct option is C $1.5 A$
Current, $I = \frac{Σ E}{Σ r}$

$= \frac{1.5 r_{1} + 1.5 r_{2} + . . . . . . . . + 1.5 r_{N}}{r_{1} + r_{2} + . . . . . . + r_{N}}$

$= 1.5 A$

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