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Concentration Terms - An Introduction (w/w etc)

A group of st...

Question

A group of students left a mixture of calcium hydroxide and water to equilibrate at $20^{\circ} C$ . They titrated the resulting saturated solution and found that if contained $0.040 mol/l$ of $O H^{-}$ ions. The solubility product constant $K_{s p} (C a (O H)_{2})$ at this temperature is therefore:

8 \times 10^{- 6}

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1.6 \times 10^{- 5}

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3.2 \times 10^{- 5}

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6.4 \times 10^{- 5}

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Solution

The correct option is C $3.2 \times 10^{- 5}$
$C a (O H)_{2} ⇌ C a^{2 +} + 2 O H^{-} S 2 S [O H^{-}] = 0.04 = 2 S \Rightarrow S = 0.02 K_{s p} = 4 S^{3} = 4 (0.02)^{3} = 3.2 \times 10^{- 5}$

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