A gun fires a bullet of mass 50 gm with a velocity of $30 m s e c^{- 1}$ because of this the gun is pushed back with a velocity of $1 m s e c^{- 1}$ The mass of the gun is

15 k g

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30 k g

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1.5 k g

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20 k g

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Solution

The correct option is B $1.5 k g$
Initial momentum =Final momentum = $m_{g} v_{g} = m_{b} v_{b}$

$(0.05 \times 30) + (m_{g} \times 1) = 0$

$\Rightarrow m_{g} = 1.5 k g$

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A gun fires a bullet of mass 50 gm with a velocity of 30msec−1 because of this the gun is pushed back with a velocity of 1msec−1 The mass of the gun is

The correct option is B 1.5kgInitial momentum =Final momentum = mgvg=mbvb (0.05×30)+(mg×1)=0 ⇒mg=1.5kg

A gun fires a bullet of mass 50 gm with a velocity of $30 m s e c^{- 1}$ because of this the gun is pushed back with a velocity of $1 m s e c^{- 1}$ The mass of the gun is

The correct option is B $1.5 k g$
Initial momentum =Final momentum = $m_{g} v_{g} = m_{b} v_{b}$

$(0.05 \times 30) + (m_{g} \times 1) = 0$

$\Rightarrow m_{g} = 1.5 k g$