A gun fires two bullets at $60^{o}$ and $30^{o}$ with the horizontal the bullets strike at same horizontal distance. The maximum heights for the two bullets are in the ratio

2 : 1

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3 : 1

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4 : 1

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1 : 1

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Solution

The correct option is B $3 : 1$
Maximum height $H = u^{2} S i n^{2} θ / 2 g$
as they at same horizontal distance and their angle of projection are complementary angle so they should have same velocity.(Off course , they have been fired from same gun.)

So ratio of maximum height $S i n^{2} 60^{0} / S i n^{2} 30^{0} = 3 / 1$
Option B is correct.

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A gun fires two bullets at 60o and 30o with the horizontal the bullets strike at same horizontal distance. The maximum heights for the two bullets are in the ratio

The correct option is B 3:1Maximum height H=u2Sin2θ/2gas they at same horizontal distance and their angle of projection are complementary angle so they should have same velocity.(Off course , they have been fired from same gun.)So ratio of maximum height Sin2600/Sin2300=3/1Option B is correct.

A gun fires two bullets at $60^{o}$ and $30^{o}$ with the horizontal the bullets strike at same horizontal distance. The maximum heights for the two bullets are in the ratio