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Question

# A gun is mounted on a railroad car. The mass of the car, the gun, the shells and the operator is 50m where m is the mass of the one shell. If the muzzle velocity of shell is 200 m/s, what is recoil speed of car after second shot?

A
20049 m/s
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B
200(148+148) m/s
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C
200(148+149) m/s
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D
200(148+148×49) m/s
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Solution

## The correct option is A 20049 m/sCentre of mass of velocity of shell = 0 (initially at rest)Therefore,0=49m×v+m×200v=−20049m/s20049m/s Another shell is fire , then the velocity of the car , with respect to platform is v′=20049m s toward left Another shell is fired , then the velocity of the car with respect to platform is v′=20048m s towards left

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