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Momentum

A gun of mass...

Question

A gun of mass $10$ kg fires $4$ bullets per second each of mass $20$ g with a velocity $300$ m/s. The force required to hole the gun is

6000

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2800

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1800

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1000

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Solution

The correct option is A $6000$ N
$\begin{matrix} M a s s o f t h e b u l l e t = 10 k g a n d v e l o c i t y o f b u l l e t = 300 m / s t h e r e f o r e f o r c e o n b u l l e t = 10 \times 4 \times 300 = 12000 f o r c e i s d i r e c t l y p r o o r t i n a l t o r a t e o f c h a n g e o f m o m e n u m t h e r e f o r e p e r sec o n d a b u l l e t a p p l i e s a f o r c e o f M V a c c l e r a t i o n = V - \frac{U}{T} U - 0 T = 1 t h e r e f o r e A - V S o, f o r c e b y o n e b u l l e t = M V = 20 \times 300 = 6000 N \end{matrix}$
Hence,
option $(A)$ is correct answer.

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