Question

A gun of mass 3 kg fires a bullet of mass 30 g. The bullet takes 0.003 s to move through the barrel of the gun and acquires a velocity of 100 m/s. Calculate :

(i) the velocity with which the gin recoils.
(ii) the force exerted on gunman due to recoil of the gun

Answer 1

Mass of bullet, m = 30 g
$$\begin{gathered} =\frac{30}{1000}\mathrm{kg} \\ =0.03\mathrm{kg} \end{gathered}$$
Velocity of bullet, v = 100 m/s
Mass of gun, M = 3 kg
$$\begin{gathered} \mathrm{Recoil}\mathrm{velocity}\mathrm{of}\mathrm{gun},\mathrm{V}=-\frac{0.03\times 100}{3} \\ \Rightarrow \mathrm{V}=-\frac{3}{3} \\ \Rightarrow \mathrm{V}=-1\mathrm{m}/\mathrm{s} \end{gathered}$$