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The Equation for the Path of Projectile

A gunman sitt...

Question

A gunman sitting a shelter fires a bullet. The shelter is at an angle $^{'} α^{'}$ to the horizontal. The gunman is at point $A$ , which is at a distance of $100$ meters from the base of the shelter as shown in the figure. The initial velocity of the gun shot is $V_{a}$ and its trajectory lies in the plane of the figure. Determine the maximum range of gunshot.

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Solution

$\frac{V_{0}^{2}}{g} sin 2 (α + {sin}^{- 1} \frac{\sqrt{100 g sin 2 α}}{V_{0}})$ .

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The Equation for the Path of Projectile

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