Question

A gymnast hangs from one end of a rope and executes vertical circular motion. The gymnast has a mass of $40kg$ and the radius of the circle is $2.5m$. If the gymnast whirls himself at a constant speed of $6m/s$, what is the tension in the rope at the lowest point? (in $N$)

• A. $1200$
  
• B. $968$
  
• C. $635$
  
• D. $125$
  

Answer 1

The correct option is B $968$

The tension in the rope at lowest point is given by $T=mg+\frac{m{v}^2}{r}$

Putting values in equation from question we have

$T=40\ast 9.8+\frac{40\ast 6^2}{2.5}=968N$