Question

A half ring of radius $R$ has a charge of $\lambda$ per unit length. The potential at the centre of the half ring is$(k=\frac{1}{4\pi {\epsilon }_0})$

• A. $k\frac{\lambda }{R}$
• B. $k\frac{\lambda }{\pi R}$
• C. $k\frac{\pi \lambda }{R}$
• D. $k\pi \lambda$

Answer 1

The correct option is D $k\pi \lambda$

We know Potential $=\frac{kQ}{R}$

$Q=\lambda \times totallength$

$V=\frac{k(\lambda \times \pi R)}{R}$

$\Rightarrow V=k\pi \lambda$