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Question
A Hall effect transducer is used for the measurement of a magnetic field of 0.5(Wb/m2). The 2mm thick slab is made of bismuth for which the Hall's co-efficient is −1×10−6(Vm/(A Wbm−2)) the current is 3A, the output voltage (in mV) is _____
- -0.75
- -0.75
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Solution
The correct option is A -0.75
EH=KHIB/t
=−1×10−6×3×0.5×12×10−3
=−10−6×0.75×103
=−75×10−5=−0.75 mV
∴EH=−0.75 mV
EH=KHIB/t
=−1×10−6×3×0.5×12×10−3
=−10−6×0.75×103
=−75×10−5=−0.75 mV
∴EH=−0.75 mV
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