A hall is constructed with length 24 m width 18 m. The sum of the areas of its floor and flat roof is equal to the surface area of its four walls. Find the height of the hall.

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Solution

Given length of hall = 24 cm
width of hall = 18 m
height of hall = 4 m
area of four walls = 2[ lb+bh]
area of four walls = 2[l+b]h
area of floor and flat roof = 2lb
Given 2[l+b]h=2lb
$2 [24 + 18] h = 2 \times 24 \times 18$
21 $42 h = 24 \times 18$
$h = \frac{72}{7}$
height of wall is $\frac{72}{7} m$

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A hall is constructed with length 24 m width 18 m. The sum of the areas of its floor and flat roof is equal to the surface area of its four walls. Find the height of the hall.

Given length of hall = 24 cmwidth of hall = 18 mheight of hall = 4 marea of four walls = 2[ lb+bh]area of four walls = 2[l+b]harea of floor and flat roof = 2lbGiven 2[l+b]h=2lb2[24+18]h=2×24×1821 42h=24×18h=727height of wall is 727m