A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is Rs.2 per $m^{2}$ . Find the total cost of carpeting the hall.

224

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Rs. 264

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Rs. 642

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Rs. 292

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Solution

The correct option is A 224
Refer to the following figure:

Area of parallelogram = Base $\times$ corresponding height = 8 $\times$ (1.75 $\times$ 8) = 112 $m^{2}$

Total cost of carpeting the hall = Cost per m² $\times$ Area = 2 $\times$ 112 = Rs. 224

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Q. A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is Rs.2 per

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A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is Rs.2 per m2. Find the total cost of carpeting the hall.

The correct option is A 224Refer to the following figure: Area of parallelogram = Base × corresponding height = 8 × (1.75 × 8) = 112 m2 ​ Total cost of carpeting the hall = Cost per m2 ×​ Area = 2 × 112 = Rs. 224

A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is Rs.2 per $m^{2}$ . Find the total cost of carpeting the hall.

The correct option is A 224
Refer to the following figure:

Area of parallelogram = Base $\times$ corresponding height = 8 $\times$ (1.75 $\times$ 8) = 112 $m^{2}$

Total cost of carpeting the hall = Cost per m² $\times$ Area = 2 $\times$ 112 = Rs. 224