A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is Rs.2 per $m^{2}$ . Find the total cost of carpeting the hall.

224

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264

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642

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292

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Solution

The correct option is A
224

Refer to the following figure:

Area of parallelogram = Base $\times$ corresponding height = 8 $\times$ (1.75 $\times$ 8) = 112 $m^{2}$

Total cost of carpeting the hall = Cost per m² $\times$ Area = 2 $\times$ 112 = Rs.224

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Similar questions

A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is ₹ 2 per $m^{2}$ . Find the total cost of carpeting the hall.

Q. A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is Rs.2 per

m^{2}

, find the total cost of carpeting the hall.

Q. The rate for a

1.2

m wide carpet is Rs.

40

per metre; find the cost of covering a hall

45

m long and

32

m wide with this carpet. Also, find the cost of carpeting the same hall if the carpet,

80

cm wide, is at Rs.

25

per metre.

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A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is Rs.2 per m2 . Find the total cost of carpeting the hall.

The correct option is A 224 Refer to the following figure: Area of parallelogram = Base × corresponding height = 8 × (1.75 × 8) = 112 m2 ​ Total cost of carpeting the hall = Cost per m2 ×​ Area = 2 × 112 = Rs.224

A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is Rs.2 per $m^{2}$ . Find the total cost of carpeting the hall.

The correct option is A
224

Refer to the following figure:

Area of parallelogram = Base $\times$ corresponding height = 8 $\times$ (1.75 $\times$ 8) = 112 $m^{2}$

Total cost of carpeting the hall = Cost per m² $\times$ Area = 2 $\times$ 112 = Rs.224