A hall is of length 23 cm, breadth 30 m and height 12m. Find the number of person the can be accommodated in the hall, assuming that $6 m^{3}$ of air is required for each person.

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Solution

First you find volume of hall $= l e n g t h \times b r e a t h e \times h e i g h t$
$= 23 \times 30 \times 12 = 8280 m^{3}$
Now $,$ no. of people in hall $= \frac{8280}{6} = 1380$
Hence $,$ number of person $= 1380.$

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A hall is of length 23 cm, breadth 30 m and height 12m. Find the number of person the can be accommodated in the hall, assuming that 6m3 of air is required for each person.

First you find volume of hall =length×breathe×height=23×30×12=8280m3Now, no. of people in hall =82806=1380 Hence, number of person=1380.

A hall is of length 23 cm, breadth 30 m and height 12m. Find the number of person the can be accommodated in the hall, assuming that $6 m^{3}$ of air is required for each person.

First you find volume of hall $= l e n g t h \times b r e a t h e \times h e i g h t$
$= 23 \times 30 \times 12 = 8280 m^{3}$
Now $,$ no. of people in hall $= \frac{8280}{6} = 1380$
Hence $,$ number of person $= 1380.$