A hammer exerts a force of 1.5 N on each of the two nails A and B. The area of cross section of tip of nail A is 2 $m m^{2}$ while that of nail B is 6 $m m^{2}$ . Calculate pressure on each nail in pascal.

Open in App

Solution

Force, $F = 1.5 N$

Area of nail A = $2 m m^{2} = 2 \times 10^{- 6} m^{2}$

Hence, pressure on nail A = $\frac{1.5}{2 \times 10^{- 6}} = 7.5 \times 10^{5} P a$

Area of nail B = $6 m m^{2} = 6 \times 10^{- 6} m^{2}$

Hence, pressure on nail A = $\frac{1.5}{6 \times 10^{- 6}} = 2.5 \times 10^{5} P a$

Suggest Corrections

181

Similar questions

Q. A nail is driven into a wooden board by using a hammer. The impact of the hammer on the head of nail produces a thrust of

25 N

. If the area of the head is

0.5 m m^{2}

and of the tip is

0.1 m m^{2}

, find the pressures on the head and on the tip of the nail.

A hammer of mass 500 g, moving at 50 m s⁻¹, strikes a nail. The nail stops the hammer in a very short time of 0.01 s. What is the force of the nail on the hammer?

Join BYJU'S Learning Program

A hammer exerts a force of 1.5 N on each of the two nails A and B. The area of cross section of tip of nail A is 2 mm2 while that of nail B is 6 mm2. Calculate pressure on each nail in pascal.

Force, F=1.5 N Area of nail A = 2 mm2=2×10−6 m2 Hence, pressure on nail A = 1.52×10−6=7.5×105 Pa Area of nail B = 6 mm2=6×10−6 m2 Hence, pressure on nail A = 1.56×10−6=2.5×105 Pa

A hammer exerts a force of 1.5 N on each of the two nails A and B. The area of cross section of tip of nail A is 2 $m m^{2}$ while that of nail B is 6 $m m^{2}$ . Calculate pressure on each nail in pascal.