A hammer of mass 1kg having speed of 50m/s hits on iron nail of mass 200gm. If the specific heat of iron is 0.105cal/gm∘C and half the energy is converted into heat, the raise in the temparature of nail is
A
7.1∘C
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B
10.5∘C
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C
12.1∘C
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D
9.2∘C
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Solution
The correct option is A7.1∘C Formula used: Q=mcΔθ
Given: M=1kg,v=50m/s,m=200g,c=0.105cal/g∘C,12KE=Q
To convert CGS unit into SI unit we use factor of J=4.2, W=JQ 12(12Mv2)=J(mcΔθ) 14×1×(50)2=4.2[200×0.105×Δθ] Δθ=7.1∘C