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Question

A hammer of mass 1 kg having speed of 50 m/s hits on iron nail of mass 200 gm. If the specific heat of iron is 0.105 cal/gmC and half the energy is converted into heat, the raise in the temparature of nail is

A
7.1C
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B
10.5C
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C
12.1C
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D
9.2C
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Solution

The correct option is A 7.1C
Formula used: Q=mcΔθ

Given: M=1 kg, v=50 m/s, m=200 g, c= 0.105 cal/gC, 12KE=Q

To convert CGS unit into SI unit we use factor of J=4.2,
W=JQ
12(12Mv2)=J(mcΔθ)
14×1×(50)2=4.2[200×0.105×Δθ]
Δθ=7.1C

FINAL ANSWER: (a).

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