A hammer of mass 1 kg moving with a speed of 6 m/s strikers a wall and comes to rest in 0.1 s, calculate Retarding force that stops the hammer.

60 N

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50 N

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40 N

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30 N

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Solution

The correct option is A 60 N
$m = 1 k g$
$u = 6 m / s, v = 0, t = 0.15$
impulse = $f \times t = m (v - u) = 1 (0 - 6) = - 6 N s$
retarding force stops the hammer
$F = \frac{I}{T} = \frac{6}{0.1} = 60 N$

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A hammer of mass 1 kg moving with a speed of 6 m/s strikers a wall and comes to rest in 0.1 s, calculate Retarding force that stops the hammer.

The correct option is A 60 Nm=1kgu=6m/s,v=0,t=0.15impulse = f×t=m(v−u)=1(0−6)=−6Nsretarding force stops the hammer F=IT=60.1=60N

The correct option is A 60 N
$m = 1 k g$
$u = 6 m / s, v = 0, t = 0.15$
impulse = $f \times t = m (v - u) = 1 (0 - 6) = - 6 N s$
retarding force stops the hammer
$F = \frac{I}{T} = \frac{6}{0.1} = 60 N$