A hammer of weight 2kg, moving with velocity 8m/s, strikes against the head of a spike, and drives it into a block of wood. If hammer comes to rest in 0.02sec, the impule associated with the spike will be:
A
30Ns
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B
−16Ns
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C
−30Ns
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D
16Ns
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Solution
The correct option is D16Ns Initial momentum of the hammer Pi=mu=2×8=16kg m/s
Final momentum of the hammer Pf=0
Change in momentum of the hammer ΔP=Pf−Pi ΔP=0−16ΔP=−16kg m/s
Impulse acting on the hammer Ihammer=ΔP=−16Ns
Impulse acting on the spike Ispike=−Ihammer=16Ns