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Question

A hammer weighing 3kg, moving with a velocity of 10m/s, strikes against the head of a spike and drives it into a block of wood. If the hammer comes to rest in 0.025s, the impulse associated with the hammer will be

A
30Ns
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B
30Ns
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C
15Ns
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D
15Ns
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Solution

The correct option is B 30Ns
Let J be the impulse associated with the hammer
then, ΔJΔt=ma and a =ΔVΔt

Hence, j = mΔV

j= 3(0 - 10) Ns = -30 Ns

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