wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A hammer weighing 3kg, moving with a velocity of 10m/s, strikes against the head of a spike and drives it into a block of wood. If the hammer comes to rest in 0.025s, the impulse associated with the hammer will be

A
30Ns
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
30Ns
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
15Ns
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
15Ns
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 30Ns
Let J be the impulse associated with the hammer
then, ΔJΔt=ma and a =ΔVΔt

Hence, j = mΔV

j= 3(0 - 10) Ns = -30 Ns

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Second Law of Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon